I need this program to work by tomorrow morning, but I can't tell that I'm doing anything wrong!!
Errors:
o_assignment5.cpp: In function `int main()':
o_assignment5.cpp:48: non-lvalue in assignment
o_assignment5.cpp:48: parse error before `-' token
o_assignment5.cpp:52: parse error before `)' token
o_assignment5.cpp:54: parse error before `)' token
o_assignment5.cpp: At global scope:
o_assignment5.cpp:61: parse error before `;' token
o_assignment5.cpp:61: syntax error before `++' token
o_assignment5.cpp:63: parse error before `;' token
o_assignment5.cpp:63: syntax error before `++' token
o_assignment5.cpp:66: syntax error before `%26lt;%26lt;' token
o_assignment5.cpp:70: syntax error before `.' token
Code:
#include %26lt;iostream%26gt;
#include %26lt;cstdlib%26gt;
#include %26lt;fstream%26gt;
#include %26lt;iomanip%26gt;
#include %26lt;cmath%26gt;
using namespace std;
const int SIZE = 15;
int colRow[SIZE][SIZE];
int userRow; // what the user of the program inputs for table width
int finalRow;
int userCol;
C++ help... Due tomorrow.?
The userRow - 1 = finalRow is not correct. I think that you mean: finalRow = userRow -1 and finalCol = userCol - 1
Try that it should compile.
But also I don't understand your loop code
the "int finalRow" will override the previously defined "finalRow" for the scope of the loop and likewise for the "int finalCol" loop.
HTH
Reply:userRow - 1 = finalRow
userCol - 1 = finalCol
Switch to
finalRow = userRow - 1
finalCol = userCol - 1
Reply:1. Look at your assignments for userRow and userCol from finalRow and finalCol
2. Your last loop isn't going to do what you intend it to.
Good luck.
Reply:1. You redeclared "outs" inside of main() ...don't do that.
2. Look at the following two lines:
userRow - 1 = finalRow // to get right number in array: rows
userCol - 1 = finalCol // to get right number in array: cols
You must place the variable to which a value is assigned in the LEFT side of the expression, like this: y = x - 1
3. One of your for() loops had a missing closing brace. Use proper indentation to find where this occurred.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment