Trig integrals?

int. (6sin^6x)(cos^3x)dx





i worked it out and got 6[(sin^7x/7)-(sin^9x/9)] + C


webassign is telling me its wrong then there's a syntax error...help?

Trig integrals?
okay well sometimes calculators are weird. maybe you typed it in wrong. like try double parentheses.





did you do a , x?





i put it in my calculator and got:





-(cos(9x)+3cos(3x))/3





but that could be totally wrong.





good luck!
Reply:I don't think its powers you want. It works if they are coeefficients of x





sin6x = 2sin3xcos3x





Thus we have





int 12sin(3x)cos^2(3x)





If u = cos(3x) then du = -3sin3x dx





=%26gt; int -4u^2 du





= -4u^3/3





y = -4cos^3(3x)/3

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