Syntax error on line 29 " ;; " unexpected?

#!/bin/ksh


while :


do


clear


cat %26lt;%26lt;++


MAIN MENU


1) Delete a file


2) Rename a file


3) Find a file


4) Display contents of a file using cat


5) Edit a file using vi


6) List the contents of a directory


7) Print current directory


8) Print today's date and time


x) Exit


++


echo "Please enter your selecton $LOGNAME \c


read selection


case $selection in


1)


echo "Enter a filename: \c


read fname


if [ -r $fname ]


then


rm $fname


else


echo " menu: Cannot access file $fname"


fi


;;


2)


echo "Enter a filename: \c"


read fname


echo "Enter a new filename \c"


read frename


if [ -r $fn ]


then


cp $fname $frename


else


echo "menu: Cannot access file $fname"


fi


;;


3)


echo "Enter a filename: \c


read fname


find . -name "$fname" -print


;;


4)


echo "Enter a filename: \c


read fname


if [ -r $fname ]


then


cat $fname


else


echo "menu: Cannot access the $fname \c"


fi


;;


5)


echo "Enter a filename: \c"


read fname


if [ -r $fname ]


then


vi $fname


else


echo "menu: Cannot access the file $fname \c"


6)


echo "Enter a directory name \c"


read dname


if [ -r $dname ]


then


ls -l $dname


else


echo "menu: Cannot access directory $dname"


fi


;;


7)


pwd


;;


8)


date


;;


q|Q|e|ExX


exit 0


;;


*) echo "Invalid choice, Try again. ";;


esac


echo "Press enter to continue \c"


done

Syntax error on line 29 " ;; " unexpected?
Your "Enter a filename \c





lines don't have a closing quote mark.





Check for other missing quote marks -- the enter selection line is also missing one.





You also have some other syntax errors -- a missing ) on the quit line and a missing fi;; just before 6).